alice and bob codeforces

Return the maximum strength he can achieve. 2). Determine the maximum score of Alice and Bob respectively. On each move, a player counts the total size of candies eaten during the current move. Can someone help me in solving this game theory problem? The rules are as follows. Alice can pick rock 'a' times, scissors 'b' times and paper 'c' times. If there are not enough candies to make a move this way, then the player eats up all the remaining candies and the game ends. Codeforces Clean Code Champions: Nominate Your Favorites! Although, the problems are much easier and many times are slight variation of the standard algorithms. Alice eats three candies with the total size of $$$1+4+1=6$$$ and the sequence of candies becomes $$$[5,9,2,6,5,3]$$$. The game ends if all the candies are eaten. The first line contains one integer n (1n105) the amount of bars on the table. 2). Also I maintain time counters for both of them, to determine whose time is to eat chocolate. Virtual contest is a way to take part in past contest, as close as possible to participation on time. 1, Div. If you need more clearification feel free to ask in the comment. Alice and Bob play an interesting and tasty game: they eat candy. Codeforces. Codeforces Round 887 (Div 1, Div 2) Tutorial, [GYM] HIAST Collegiate Programming Contest 2023, Codeforces Round #884 (Div. If both players start to eat the same bar simultaneously, Bob leaves it to Alice as a true gentleman. 1 + Div. Alice and Bob CodeForces - 347C - Programmer Sought Thanks for you response. $$$a$$$ the total size of all sweets eaten by Alice during the game; $$$b$$$ the total size of all sweets eaten by Bob during the game. If the number of them is even, then nothing can be done because if you want to skip the turn the opponent can always skip back. Trying to solve an old Topcoder TCO06 problem, Invitation to Codeforces Round 887 (Div. The They get a set of n distinct integers. 3) Interesting Facts, Alternate Solution for 1787-G (Colorful Tree Again). Codeforces Clean Code Champions: Nominate Your Favorites! either Alice or Bob (the player whose turn is the current) can choose two distinct integers x and y from the set, such that the set doesn't contain their absolute difference . If the number of stones with value 0 is odd, then the loser is the opposite (because of the third observation). If the number of stones with value 0 is odd, then the loser is the opposite (because of the third observation). You will keep alternating between them after that, and the loser is the one who runs out of stones of the type he wants that turn (you also need to think of the scenario where all of the stones run out, which is really annoying). The function getDivideIndexRec(int[] arr, int i, int j, boolean isLeft) is the heart of the solution. Codeforces Round #778 C. Alice and the Cake - Programmer All [Screencast] Somehow getting top 5 in Codeforces Round 888 (Div. 1 + Div. If the number of stones with value 0 is odd, then the loser is the opposite (because of the third observation). Solving CodeForces Problem E (Div.3) Alice and Bob have decided to play the game "Rock, Paper, Scissors". 2), [GYM] The 2023 Damascus University Collegiate Programming Contest, Codeforces Round 888 (Div. Please Help !!!!!!!!!! 1, Div. 2) flamestorm April Fools Day Contest 2023 . Bob will pick any connected component(containing all or some nodes), Alice will pick any remaining connected components if there are any. Brute force. I participated in the lowe's coding round and there was this question I was not able to solve completely. GitHub: Let's build from here GitHub This problem can be easily solved using properties of deque,below is the implementation of the same::: The only programming contests Web 2.0 platform, Educational Codeforces Round 152 (Rated for Div. Third observation: stones with value 0 essentially skip the turn. Build the DFS tree (shamelessly linking to my own blog, oh no) of the graph. Problem link: http://codeforces.com/problemset/problem/6/C. GitHub: Let's build from here GitHub If the number of them is even, then nothing can be done because if you want to skip the turn the opponent can always skip back. Hello everyone. 3)!!! Alice starts to eat chocolate bars one by one from left to right, and Bob from right to left. . Yes, your solution will work (not exactly how you have described, but there is definitely an intuitive iterative implementation). 3) Interesting Facts, Alternate Solution for 1787-G (Colorful Tree Again). It is necessary to solve the questions while watching videos, nados.pepcoding.com enables that.NADOS also enables doubt support, career opportunities and contests besides free of charge content for learning. I tried to solve the problem recursively. AliceBob : Codeforces Problem 6C. What connected components are there after removing the vertex $$$u$$$? Second observation: you can never start with a stone that has value 0, so you will have to pick either one with value 1 or 2. 2), [GYM] The 2023 Damascus University Collegiate Programming Contest, Codeforces Round 888 (Div. Given the tree, Alice's guesses, and the value of for each game, find the probability that Alice will win the game and print it on a new line as a reduced fraction in the format p/q. Alice moves first and she may break a node. Trying to solve an old Topcoder TCO06 problem, Invitation to Codeforces Round 887 (Div. Codeforces separates its users into 4 divisions by their rating: For Division 1: 1900rating For Division 2: 1600rating1899 For Division 3: 1400rating1599 For Division 4: rating1399 Given a rating, print in which division the rating belongs. Alice and Bob like games. Input For me, I think better recursively than iteratively. GitHub: Let's build from here GitHub Input: number of test cases then n, m and then sweetness of each node and then the edges. Can you explain exactly why you think so ? Please Help !!!!!!!!!! Alice starts to eat chocolate bars one by one from left to right, and Bob from right to left. It has created a lot of desperate people who do not actually care about competitive programming but need to be good anyway. 2). Alice eats two candies with the total size of $$$5+9=14$$$ and the sequence of candies becomes $$$[2,6]$$$. Codeforces-346A-Alice and Bob (more phase loss) - Programmer Sought It is so boring in the summer holiday, isn't it? The only programming contests Web 2.0 platform. The order you need to take the stones is fixed. Can someone help me in solving this game theory problem? A tag already exists with the provided branch name. Explanation: There is no way for Alice to win the game. [Screencast] Somehow getting top 5 in Codeforces Round 888 (Div. move 2: Alice ate $$$3$$$ on the previous move, which means Bob must eat $$$4$$$ or more. 2), [GYM] The 2023 Damascus University Collegiate Programming Contest, Codeforces Round 888 (Div. Codeforces Round 887 (Div 1, Div 2) Tutorial, [GYM] HIAST Collegiate Programming Contest 2023, Codeforces Round #884 (Div. So Alice and Bob have invented a new game to play. 3) Interesting Facts, Codeforces, Alternate Solution for 1787-G (Colorful Tree Again). Alice_and_Bob - Codeforces Submissions Expert Alice_and_Bob Contest rating: 1724 (max. What is optimal way of doing this problem. This one came in 1st round. The second line contains a sequence of integers $$$a_1, a_2, \dots, a_n$$$ ($$$1 \le a_i \le 1000$$$) the sizes of candies in the order they are arranged from left to right. So Alice and Bob have invented a new game to play. [Screencast] Somehow getting top 5 in Codeforces Round 888 (Div. "/> art malik true lies. Once this number becomes strictly greater than the total size of candies eaten by the other player on their previous move, the current player stops eating and the move ends. # include <stdio.h>. isLeft also gives priority to Alice over Bob if both attampt to eat the same chocolate. How would you handle partial cases, say at a given moment Alice finishes hers when Bob is still eating. Can you please elaborate further because my dfs gave me TLE. CodeForces - 347C Alice and Bob. If no connected component left, alice gets 0. Alice and Bob play an interesting and tasty game: they eat candy. Input The first line of the input contains an integer t (1t104) the number of testcases. The process consists of moves. Your email address will not be published. 2022 Woodward Dream Cruise. Example 2: Input: n = 3 Output: false Explanation: Alice chooses 1, Bob chooses 1, and Alice has no more moves. For each chocololate bar the time, needed for the player to consume it, is known (Alice and Bob eat them with equal speed). Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. Thus, we can check the scores of both players if Alice removes the vertex $$$u$$$ at first. Solution: test for picking a stone with value 1 first, then for picking a stone with value 2 first. Codeforces Round 887 (Div 1, Div 2) Tutorial, [GYM] HIAST Collegiate Programming Contest 2023, Codeforces Round #884 (Div. PepCoding | Alice And Bob Alice will get all the pieces marked A and Bob will get all the pieces marked B. Can someone help me in solving this game theory problem? First observation: the values of the stones by themselves doesnt matter, what matters is their value mod 3. After you pick a stone with value 2, you cant pick a stone with value 1, so you will have to pick a stone with value 2, and then you will have to pick a stone with value 1, and them two, and so it goes. Hence the solution. {"payload":{"allShortcutsEnabled":false,"fileTree":{"":{"items":[{"name":"A and B and Compilation Errors.cpp","path":"A and B and Compilation Errors.cpp","contentType . move 4: Alice ate $$$6$$$ on the previous move, which means Bob must eat $$$7$$$ or more. 2), [GYM] The 2023 Damascus University Collegiate Programming Contest, Codeforces Round 888 (Div. Blog Teams Submissions Contests Ambuj123's blog Codeforces Round #640 (Div. Assume both plays the game optimally. Alexdat2000 Codeforces Round #862 (Div. [Screencast] Somehow getting top 5 in Codeforces Round 888 (Div. In the following, I'll denote as $$$\mathrm{sw}[u]$$$ the sweetness value of $$$u$$$. Third observation: stones with value 0 essentially skip the turn. 2), [GYM] The 2023 Damascus University Collegiate Programming Contest, Codeforces Round 888 (Div. The problem says, You are given a connected undirected graph. If both players start to eat the same bar simultaneously, Bob leaves it to Alice as a true gentleman. Alice, Bob, Two Teams CodeForces - 632B - Programmer Sought They have placed n chocolate bars in a line. D - Alice, Bob and Candies CodeForces - 1352D - 2). Alice and Bob plays break the node - Codeforces Print two numbers a and b, where a is the amount of bars consumed by Alice, and b is the amount of bars consumed by Bob. You will keep alternating between them after that, and the loser is the one who runs out of stones of the type he wants that turn (you also need to think of the scenario where all of the stones run out, which is really annoying). The order you need to take the stones is fixed. First observation: the values of the stones by themselves doesnt matter, what matters is their value mod 3. From now on when i talk about value im talking about the value mod 3. Never use someone else's code, read the tutorials or communicate with other person during a virtual contest. In particular, what matters is the ammount of each stone on each mod value. Each test case consists of two lines. . 1 + Div. E. Alice, Bob, Oranges and Apples Alice and Bob decided to eat some fruit. Blog Teams Submissions Contests case3's blog Alice and Bob plays break the node By case3 , history , 2 years ago , Hello everyone. It is guaranteed that the sum of the values of $$$n$$$ for all sets of input data in a test does not exceed $$$2\cdot10^5$$$. Both of them want to maximize their score by collecting maximum possible sweetness. For each chocololate bar the time, needed for the player to consume it, is known (Alice and Bob eat them with equal speed). Thats the link to my submission: http://codeforces.ru/contest/6/submission/5291991. 4) D. Alice, Bob and Candies After you pick a stone with value 2, you cant pick a stone with value 1, so you will have to pick a stone with value 2, and then you will have to pick a stone with value 1, and them two, and so it goes. 2), [GYM] The 2023 Damascus University Collegiate Programming Contest, Codeforces Round 888 (Div. Find the player who will win by choosing a number in range [1, K] with When Alice picks any number from 1 to 7 (inclusive both), the opponent wins the game in the next turn by making the total 8 . Solution: test for picking a stone with value 1 first, then for picking a stone with value 2 first. For each chocololate bar the time, needed for the player to consume it, is known (Alice and Bob eat them with equal speed). [Screencast] Somehow getting top 5 in Codeforces Round 888 (Div. These hiring challenges are really destroying competitive programming.