sum of multiples of 3 and 5 in java

The sum of these multiples is 23. Multiples of 3 and 5 In a mathematical perspective, The trick here is to apply the formula for multiples of three and for five, then remember that multiples of fifteen will have been counted twice. Develop fluency in 67 programming languages The statement of the problem is to sum the multiples of 3 and 5 below 1000, not up to and equal 1000. Use two different counters. As @Yunnosch says don't use a loop to calculate the sum. WebIf we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. (I'm using a website called Project Euler.net to help me practice code. 1116 Solvers. Java Browse other questions tagged, Where developers & technologists share private knowledge with coworkers, Reach developers & technologists worldwide, The future of collective knowledge sharing, Improving time to first byte: Q&A with Dana Lawson of Netlify, What its like to be on the Python Steering Council (Ep. The sum of these multiples is 23. Edit the title and the question to have better phrasing. Multiples of 3 and 5, multiples of 5 and multiples of 3 in Java Ask Question Asked 7 years, 9 months ago Modified 5 years, 4 months ago Viewed 4k times T and thus our overall formula for the sum of all multiples of 3 becomes 3 \times \sum {x/3} 3x/3. Exercism is fun, effective and I appreciate the 2 line java 8 treatment but fail to see how it offers a complexity improvement. For this exercise, we're going to consider all numbers below 1000 that are multiples of either 3, or 5. Finding the sum of 3 numbers with 5 positive integer divisors. Why only multiples of 2 numbers? Your task is to write the code that calculates the energy points that get awarded to players when they complete a level. LCM (least common multiple) should be $3\times 5 = 15$. */, /* " " " " " " */, /*W: used for formatting 'e' part of Y. If the remainder when the argument (n) is divided by 100 is zero, it means that the number is a multiple of 100. {\displaystyle i} extra set of numbers started with $15$ all the way to $990$ that How to find the sum of all the multiples of 3 or 5 below 1000 in Python? Another FORTH version using the Inclusion/Exclusion Principle. WebFind the sum of all the multiples of 3 or 5 below 1000. Should I trigger a chargeback? Or, more generally taking the area under the straight line between the first multiple and the last: Extra credit, using the summation formula: Here's an analytical approach that scales much better for large values. Find multiples. So the products of 15 can also be divided by those number as well! Since all integers are arbitrary precision in Nanoquery, it is possible to use this solution for large n, but it is inefficient. 225 , The sum of these multiples is . Compute the sum of multiples of 3 and add to sum. Input: N = 100, A= 5, B= 10 Output: Sum = 950. Project Euler > Problem 1 > Multiples of 3 and 5 (Java Solution ;). To solve this problem, we will use the Help please: Find the sum of all the multiples of 3 or 5 below 1000. If you like GeeksforGeeks and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to review-team@geeksforgeeks.org. Project Euler: Problem 1, Multiples of 3 and 5 minimalistic ext4 filesystem without journal and other advanced features, Physical interpretation of the inner product between two quantum states. Sum of multiples of Array elements within a given range I also tried to change the variable value to boolean and then I got different errors. Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. 630 , If you need to know the count of the How do I figure out what size drill bit I need to hang some ceiling hooks? n The only question which give me trouble is that why I have to subtract the sum of 15?! 195 , I haven't attempted the extra credit here as the math is too complex for me at the moment. java The calculations could be conducted in double precision (or better, quadruple precision), a trivial modification to the source. .And because we all will need java-8 and lambdas oneday As you go through the numbers from 1 to 1000, you can add the multiple of 3 to a list. Determine the multiples. Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. Counting multiples of 3 up to a given number. US Treasuries, explanation of numbers listed in IBKR. Your answer is 266333 Use the math formula based on the famous Triangular number formula for summing the integers between 1 and n, i.e. This is actually Project Euler problem no 1 and can be solve efficiently by using mutual inclusion exclusion. Create a function called mulitples0f It will accept two arguments, the first will be an array of numbers, the second will be a number. The sum of these multiples is 23. Thanks for contributing an answer to Stack Overflow! Using robocopy on windows led to infinite subfolder duplication via a stray shortcut file. How can I avoid this? followed by T lines each containing an integer N. The one who posted the answer 233168, please explain that answer in detail . For example: if num is 10, the multiples of 3 and 5 that are below 10 are 3, 5, 6, and 9, and adding them up you get 23, so your program should return 23. Find the multiples. 375 , Multiples of 3 and 5 I wrote the following code to get all of the numbers from 0 to 1000 that are multiples of three: Now I would like to add these numbers together and print the result after the loop. This is important in programming, because it helps us to find answers and make decisions. No need to test for multiplicity of 3 if you iterate by multiples of 3. A little extra code was added to format the output nicely. WebJava Integer sum() Method. */, 'The sum of all positive integers that are a multiple of 3 and 5 are:', /* [] change the format/look of nE+nn*/, /*this fixes a bug in a certain REXX. n: Sum_35 (n)", "-----------------------------------------------------------------", ----------------- SUM MULTIPLES OF 3 AND 5 -----------------, --------------------------- TEST ---------------------------, -- sum35Result:: String -> Int -> Int -> String, -- sums of all multiples of 3 or 5 below or equal to N, -- for N = 10 to N = 10E8 (limit of AS integers), -------------------- GENERIC FUNCTIONS ---------------------, -- foldl:: (a -> b -> a) -> a -> [b] -> a, -- Lift 2nd class handler function into 1st class script wrapper, "Sum of positive integers below 1000 divisible by 3 or 5 is: ", "The sum of numbers divisible by 3 or 5 between 1 and {0} is {1}", //--------------------------------------------------------------------------------------------------, // this method uses less than half iterations than the first one, ;; using simple arithmetic - young Gauss formula. Factorizing the sum of those by n we get: n(1+2+3+ m//n). T The sum of these multiples is 23. 330 , Problem. It can't be, because the last number multiple 2 is 98. 765 , The Ruby version sums up to and including n. Find the sum of all the multiples of 3 or 5 below 1000. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. By clicking Post Your Answer, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct. If the user inputs the number, only inputs multiples of 15, it will display "CS", "Computer" for multiples of 5 and "Science" for multiples of 3. 4. Browse other questions tagged, Where developers & technologists share private knowledge with coworkers, Reach developers & technologists worldwide, The future of collective knowledge sharing. sum WebSum Multiples of Three and Five - Java Exercise with Solutions Sum Multiples of Three and Five Given a number n, write a method that sums all multiples of three and five up Something like, Based on your comment below, change main to first read the int of counts, then store them in an array. The product of two successive integral multiples of 5 is 300. Compute the sum of multiples of 5 and add to sum. More cases to check for. NB. 5 As Nim doesnt provided them in its library, we have to use a third party library, either "bigints" or "bignum". Browse other questions tagged, Where developers & technologists share private knowledge with coworkers, Reach developers & technologists worldwide, The future of collective knowledge sharing, Re-read your code, you are writing a lot of unnecesseray lines. The concept of the partially -multi-threaded version: we have a value sum, where we add together all the multiples of 3 (that are not multiples of 3 and 5). Help us improve. }, //sum of all positive multiples of 3 or 5 below n, # Machine precision was sufficient for the first calculation, // Number of multiples of $divisor <= $max, # Calculate the sum of the multiples of 3 and 5 up to 1000, # Calculate the sum of the multiples of 3 and 5 up to 10 ^ 210, "Sum of numbers below 1000 which are multiples of 3 or 5 is: ", "Count all the 3's; all the 5's; minus double-counted 3*5's", 'Sum the arithmetic progressions: sum3 + sum5 - sum15', '''Summed multiples of 3 and 5 up to n''', # TEST ----------------------------------------------------, '''Tests for [10^1 .. 10^5], and [10^8 .. 10^25], # GENERIC -------------------------------------------------, # compose (<<<):: (b -> c) -> (a -> b) -> a -> c, '''Right to left function composition. multiples of 3 } number n, count all multiples of 3 Solution of Project Euler Problem 1 in Java - Print sum of all multiples of 3 or 5 below 1000. sum As we know that we need to sum of those numbers which are divisible by 3 or 5 below n where n=10 or 100 or more (it is limit). 660 , The same formula can be used for 5: The sum of all numbers divisible by 5 is 5 \times \sum {x/5} 5x/5. WebIN JAVA!!!!! // fTable:: String -> (a -> String) -> (b -> String), // -> (a -> b) -> [a] -> String, // Returns Infinity over objects without finite, // length. The program must do the following: Use a while loop to calculate the sum of the odd numbers 1-25. 1: Multiples of 3 and 5 Uses the IPints library when the result will be very large. for(int i=1;i<1000;i++){ Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. When a player finishes a level, they are awarded energy points. Problem Description: If we list all the natural numbers below 10 that are multiples of 3 or 5, we ("\nThe sum of all multiples of 3 or 5 below 1000 is : "+sum);}} Reply Delete. Code: int main() { int sum = 0; int i; for (i=0; i < Remember Me? Java programming exercises and solution: Write a Java program to print numbers between 1 and 100 divisible by 3, 5 and both. 300 , The sum of these multiples is 23. ), Find the sum of all the multiples of 3 or 5 below 1000, Sum of numbers under 10,000 that are multiples of 3, 5 or 7 in Java. How does hardware RAID handle firmware updates for the underlying drives? Find count of multiples of 3 sum Am I in trouble? Find the sum of all the multiples of or below . java This took between 20 and 30 minutes to run. The base value of each magical item collected by the player during that level. Examples : Input : N = 5 Output : 4 Input : N = 10 Output : 8. 30 , is Find the sum of all the multiples of 3 or 5 below 1000, Stack Overflow at WeAreDevelopers World Congress in Berlin. \$\endgroup\$ candied_orange. If you are using Java 8 you can do it in the following way: Integer sum = IntStream.range(1, 1000) // create range Correct answer is 233168. Multiples of 3 and 5 {\displaystyle i} But the same evaluates the result in milliseconds when using a simple formula of Arithmetic Progression. the question is to add all the multiples of 3 or 5. using the FOR loop we can get all the numbers from 0 to 1000, and by using the IF condition we get the required java - The sum of all the multiples of 3 or 5 below N You can't use the same counter for both arrays. + count = count + (i * 3); We can do much better by observing that the sum of the multiples of WebIf we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. */, /*handle a special case of a onetimer. 675 , // Java program to find count of multiples // of 3 and 5 in {1, 2, 3, ..n} import java .io. Here is a cmdlet that will provide the sum of unique multiples of any group of numbers below a given limit. Find centralized, trusted content and collaborate around the technologies you use most. Introduction to Java. 592), Stack Overflow at WeAreDevelopers World Congress in Berlin, Temporary policy: Generative AI (e.g., ChatGPT) is banned. Let's ignore the "sum" for now and just focus on the numbers. For this exercise, we're going to consider all numbers below 1000 that are multiples of either 3, or 5. Recommended: Please try your approach on {IDE} first, before moving on to the solution. Note: If the number is a multiple of both 3 and 5, only count it once. Why the ant on rubber rope paradox does not work in our universe or de Sitter universe? If we list all the natural numbers below that are multiples of or , we get and . 105 , / 810 , 2333333333333333333316666666666666666668 Finally, to add numbers you should be performing arithmetic. "The sum of multiples of 3 or 5 below 1000 is ${sum35(1000)}", "The sum of multiples of 3 or 5 below 1e20 is ${sum35(e20)}", 'The sum of multiples of 3 or 5 between 1 and ', # If it's big enough that the result might not. Note: If a number less than N is divisible by both 2 or 3, or 3 or 5, or all of 2,3 and 5 then also it should be counted only once. 2. Fast version using GNU Multiple Precision library. So the sum of all numbers less than 1000 that divides 3 is. Multiples of 3 or 5 (A modification to) Jon Prez Laraudogoitas "Beautiful Supertask" time-translation invariance holds but energy conservation fails? Can anyone help me? T If number is 10 then multiple of 3 is 3,6,9 and multiple of 5 is 5,10 total sum is 33 and program gives same answer: To subscribe to this RSS feed, copy and paste this URL into your RSS reader. Poker Series 04: isFlush. is the What we really need to do is: How to Find Total Sum of Multiples of 3 or 5 in Java - YouTube and let's discuss it. public class MultiplesOf3And5 { public static void main(String[] args){ System.out.println("The sum of the multiples of 3 and 5 is: " + getSum()); } private static int getSum() { int sum = 0; for (int i = 1; i < 1000; i++) { if (i % 3 == 0 || i % 5 == 0) { sum Not the answer you're looking for? Can somebody be charged for having another person physically assault someone for them? You are trying to sum all numbers like this 3 + 6 + 9 1000 and 5 + 10 + 15 +20 + 1000 this is the same of having 3 * (1 + 2 + 3 + 4 + + 333) and 5 * ( 1 + 2 + 3 + 4 + + 200), the sum of 'n' natural number is (n * (n + 1)) (source) so you can calculate in a constant time, as it follows: You are counting some numbers twice. Output: The sum of the multiples of 3 or 5 < 1000 is 233168The sum of the multiples of 3 or 5 < 1000 is still 233168For 10^20 - 1, the sum is Sometimes, we need to find the sum of all integers or numbers that are completely divisible by 3 and 5 up to thousands, since thousands are a too large number thats why it becomes difficult for us. Implements both the naive method and inclusion/exclusion. maybe store the values in arrays and check for doubles before finalizing the answer. WebInstructions Your task is to write the code that calculates the energy points that get awarded to players when they complete a level. The sum of these multiples is 23. Multiples of 3 and 5, multiples of 5 and multiples of 3 in 101 -> 23102 -> 2318103 -> 233168104 -> 23331668105 -> 2.333316668E+9106 -> 2.33333166668E+11107 -> 2.333333166667E+13108 -> 2.333333316667E+15, Save this into file "sum_multiples_of3and5.awk". This program is pretty unsophisticated; the only optimization is that we skip testing whether It said that the int variable for value is not compatible with the boolean statements when I add them. Multiples of 3 or 5 (6kyu) [JavaScript This sum is $(a)=3983$, Count all the #s divisible by $3$: From $3$ to $990$ there are // composition of all the functions in fs. By using our services, you agree to our use of cookies. Precise results would require the introduction of multi-precision arithmetic. For integers which are multiples of both 3 and 5 print CS. The multiples of x below y form an Arithmetic Progression (AP), x, 2x, 3x nx. The correct answer is \begin{eqnarray} \sum_{k_{1} = 1}^{333} Let's look at an example: The player completed level 20 and found two magical items with base values of 3 and 5. The sum of the multiples of 3 or 5 can be calculated quite simple by looping from 1 to 999 and check what numbers are divisible by 3 and 5: To learn more, see our tips on writing great answers. This version automatically adjusts the numeric digits. Then, you could go through that list, and add each number in that list to a sum. Instead of looping twice with one condition each, loop once with two conditions (connected with an "or"). 46 Solvers. Thank you for your valuable feedback! 8. May I reveal my identity as an author during peer review? Find the sum of all multiples of 2 and 5 below N. 2. Additionally, if the number is negative, return 0 (for languages that do have them). { Program has a brute-force approach for n=1000, and also inclusion/exclusion for larger values. 270 , But when the data ranges grows more than 1010 program takes more than hours to process the result with loops. python No need to test for multiplicity of 3 if you iterate by multiples of 3. The sum of these multiples is 23. 450 , 585 , Others have already pointed out the mistakes in your code, however I want to add that the modulus operator solution is not the most efficient . A 5 is a multiple of five. 100% free, forever. count = count + (i * 5); Comparison operators are used to compare two values (or variables). English abbreviation : they're or they're not, Anthology TV series, episodes include people forced to dance, waking up from a virtual reality and an acidic rain. 6 is a multiple of 3. multiples of 3 and 5 Thanks for contributing an answer to Stack Overflow! This enables zip and zipWith to choose. (that is, summing the multiples of three and the multiples of five, and then subtracting the multiples of 15 which were double-counted).